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Physics · High School · Mechanics

Work, energy & power

The idea

When a force pushes an object through a distance, it transfers energy — that transfer is work: W = Fd cos θ, where θ is the angle between the force and the displacement. Work is measured in joules (1 J = 1 N·m). A force perpendicular to the motion does zero work, and a force opposing the motion does negative work, draining energy. You already know energy moves between forms; work is the mechanism by which forces move it.

The payoff is the work-energy theorem: the NET work done on an object equals its change in kinetic energy, where KE = ½mv². This often replaces a messy force-and-acceleration analysis with simple bookkeeping between two snapshots. Power then measures how fast the energy flows: P = W/t in watts (1 W = 1 J/s), or equivalently P = Fv for a force applied at speed v.

A common trap is thinking effort equals work. Holding a heavy barbell motionless feels exhausting, but physics says zero work is done on it because the displacement is zero. Likewise, carrying a bag horizontally at constant speed does no work against gravity, since the supporting force is perpendicular to the motion. Work demands a force component along the displacement.

Worked example

An electric motor lifts a 50 kg crate vertically through 12 m at constant speed, taking 15 s. How much work does the motor do on the crate, and what average power does it deliver?

  1. Constant speed means zero acceleration, so the lifting force exactly balances gravity: F = mg = 50 × 9.8 = 490 N upward.
  2. The force and the displacement point the same way (both upward), so θ = 0° and W = Fd = 490 × 12 = 5880 J.
  3. Interpret the number: the crate's kinetic energy never changed, so all 5880 J became gravitational potential energy — exactly mgh = 50 × 9.8 × 12.
  4. Divide by the time to get power: P = W/t = 5880/15 = 392 W.
  5. Sanity-check the scale: 392 W is about half a horsepower (746 W), a believable rating for a small hoist motor lifting 50 kg at a calm 0.8 m/s.

Answer. The motor does 5880 J of work on the crate and delivers an average power of about 392 W.

Check your understanding

  • Why does a waiter carrying a tray across a level room do no work on the tray, even though his arm gets tired?
  • How does the work-energy theorem let you skip finding acceleration in problems where the force varies in a complicated way?
  • If the same crate were lifted in half the time, what would change about the work done and what would change about the power?
  • When a force does negative work on an object, where does the object's energy go — and can you give a concrete example?

Build the foundations first

Work, energy & power builds on these concepts. If any feel shaky, start there.

Kinetic & potential energyEnergy transfer & conservationSimple machinesAlgebraic expressions · Mathematics
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