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Chemistry · University · Atomic & molecular structure

Intermolecular forces

The idea

Intermolecular forces (IMFs) are the attractions between molecules — far weaker than the covalent bonds within them, yet they decide boiling points, melting points, viscosity, surface tension, and solubility. The hierarchy you need: London dispersion forces act between all molecules and grow with electron count and contact area; dipole–dipole forces add on for polar molecules; hydrogen bonding — an especially strong dipole interaction requiring H bonded directly to N, O, or F — adds the most per interaction; ion–dipole forces dominate when ions dissolve in polar solvents.

The comparison strategy is sequential: first match molar masses to hold dispersion roughly constant, then ask which molecule carries the stronger additional force. Shape matters too — a long unbranched chain offers more contact area than its compact branched isomer, so it boils higher despite identical formula. Polarity comes straight from your VSEPR analysis: a molecule needs both polar bonds and a shape that fails to cancel them.

Two corrections to common errors: boiling water breaks hydrogen bonds between molecules, never the O–H covalent bonds inside them; and dispersion is not always the weakest player — in large molecules its cumulative effect can outweigh hydrogen bonding, which is why nonpolar candle wax is a solid while hydrogen-bonding ethanol is a liquid.

Worked example

Butane (CH₃CH₂CH₂CH₃, 58 g/mol), acetone (CH₃COCH₃, 58 g/mol), and 1-propanol (CH₃CH₂CH₂OH, 60 g/mol) have nearly identical molar masses. Rank their boiling points from lowest to highest and justify the order.

  1. Equal molar masses and similar sizes mean the dispersion contributions are comparable, so the ranking will be decided by the additional forces each molecule can form.
  2. Butane is a pure hydrocarbon with essentially nonpolar bonds — dispersion only, so it should boil lowest; indeed it is a gas at room temperature (bp about −1 °C).
  3. Acetone has a polar C=O group and a bent-at-carbonyl shape that leaves a net dipole, adding dipole–dipole attraction; but its hydrogens sit on carbon, not oxygen, so it cannot hydrogen-bond to itself. It boils in the middle (about 56 °C).
  4. 1-Propanol carries an O–H group: hydrogen bonding between molecules is the strongest IMF available here, so it boils highest (about 97 °C).
  5. Sanity-check the spread: each added force type lifts the boiling point by tens of degrees at constant mass — exactly the staircase the data shows: −1 °C, 56 °C, 97 °C.

Answer. Butane < acetone < 1-propanol (about −1 °C, 56 °C, and 97 °C), because at matched molar mass the boiling point tracks dispersion-only < dipole–dipole < hydrogen bonding.

Check your understanding

  • Why must you compare molecules of similar molar mass before crediting a boiling-point difference to dipoles or hydrogen bonds?
  • How can a molecule with very polar bonds, like CO₂, still have zero dipole moment, and which force is left to hold its solid together?
  • What changes about hydrogen bonding when a molecule can donate H-bonds versus only accept them, and how does that show up in boiling points?
  • Why does pentane boil 27 °C higher than its isomer neopentane even though their formulas are identical?

Build the foundations first

Intermolecular forces builds on these concepts. If any feel shaky, start there.

Covalent bondingStates of matter & gas lawsThe periodic table & periodic trendsElectric charge & electric fields · Physics
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